5(x^2+4)=2(10-x)

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Solution for 5(x^2+4)=2(10-x) equation: 


Simplifying
5(x2 + 4) = 2(10 + -1x)

Reorder the terms:
5(4 + x2) = 2(10 + -1x)
(4 * 5 + x2 * 5) = 2(10 + -1x)
(20 + 5x2) = 2(10 + -1x)
20 + 5x2 = (10 * 2 + -1x * 2)
20 + 5x2 = (20 + -2x)

Add '-20' to each side of the equation.
20 + -20 + 5x2 = 20 + -20 + -2x

Combine like terms: 20 + -20 = 0
0 + 5x2 = 20 + -20 + -2x
5x2 = 20 + -20 + -2x

Combine like terms: 20 + -20 = 0
5x2 = 0 + -2x
5x2 = -2x

Solving
5x2 = -2x

Solving for variable 'x'.

Reorder the terms:
2x + 5x2 = -2x + 2x

Combine like terms: -2x + 2x = 0
2x + 5x2 = 0

Factor out the Greatest Common Factor (GCF), 'x'.
x(2 + 5x) = 0


Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(2 + 5x)' equal to zero and attempt to solve:

Simplifying
2 + 5x = 0

Solving
2 + 5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 5x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5x = 0 + -2
5x = 0 + -2

Combine like terms: 0 + -2 = -2
5x = -2

Divide each side by '5'.
x = -0.4

Simplifying
x = -0.4
Solution
x = {0, -0.4}

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